Implementation of correct hashcode

Scenario:

I have one class Employee That have some filed and Employee also implemented Hash code and equals method

Case 1: Hashcode () was implemented such that it always return some random no for every object.

Like for same object also returning different hascode

Case2: Hashcode () was implemented such way it return same hashcode for all object may me they object are same or different.

What is the output of following program?

public class HascodeTest {

           

            public String name;

           

            public static void main(String[] args) {

                        HashMap test=new HashMap();

                        HascodeTest ht=new HascodeTest("test");

                       

                       

                        test.put(ht,"hello");                 

                        test.put(ht,"hello");

                        test.put(ht,"hello");

                        test.put(ht,"hello");

                        test.put(ht,"hello");

                        System.out.println("HashmapSize"+test.size());

                        System.out.println(ht);

            }

public HascodeTest(String name) {

                        super();                       

                        this.name = name;

            }

            @Override

            public boolean equals(Object obj) {

                        // TODO Auto-generated method stub

                        return super.equals(obj);

                        //return true;

            }

            @Override

            public int hashCode() {

                        // TODO Auto-generated method stub

                        int hashcode=super.hashCode();

                        System.out.println("HashCode:"+hashcode);            

                        int renVal=(int) (31 * Math.random());

                        System.out.println("HashCode"+renVal);

                        return renVal;

                        //return 3  in case 1;

            }

            @Override

            public String toString() {

                        System.out.println("Calling to String ");

                        return this.name;

                       

            }         

}

Ans:

Case 1 :Size of hashmap is 4

Case2:size of hashmap is 1

First it checks if hashode are same then only he goes for equity check and key are equal or not 
i.e if (e.hash == hash && ((k = e.key) == key || key.equals(k)))

So if hashocode are different then it has not check equals.

So implementation of correct hashcode is very important